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pkh
Since 27 Feb 2005
6549 Posts
Couve / Hood
Honored Founder
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 Fri Aug 31, 07 8:25 am |
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| FlyinElvis wrote: |
but that's exactly why I brought up on the other thread to try and find a spot for instruction that is out of the way of riding!!! so we don't get pummeled, or worse! |
Wells Island  |
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pkh
Since 27 Feb 2005
6549 Posts
Couve / Hood
Honored Founder
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| Fri Aug 31, 07 8:34 am |
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Check out my new helmet:
Bring on the tomhawks!  |
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tinyE
Since 21 Jan 2006
2004 Posts
not really an
XTreme Poster
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| Fri Aug 31, 07 8:44 am |
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| lol... now you need a mohawk like that dude... |
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Kataku2k3
Since 14 Aug 2005
3753 Posts
Los Angeles, CA
Videographer
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| Fri Aug 31, 07 8:54 am |
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Just did a few actual calculations to follow up Hein for fun! Started with sherical volume, so as not to account in for any "unnecessary space".
This is assuming we're dealing with 18 and 23m lines with a 2.5m tall kite.
(4/3)pi(18+2.5)^3 =~9022m^3
4
(4/3)pi(23+2.5)^3 =~17364m^3
4
WOW! |
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tinyE
Since 21 Jan 2006
2004 Posts
not really an
XTreme Poster
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| Fri Aug 31, 07 9:11 am |
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| Kataku2k3 wrote: | Just did a few actual calculations to follow up Hein for fun! Started with sherical volume, so as not to account in for any "unnecessary space".
This is assuming we're dealing with 18 and 23m lines with a 2.5m tall kite.
(4/3)pi(18+2.5)^3 =~9022m^3
4
(4/3)pi(23+2.5)^3 =~17364m^3
4
WOW! |
but that's the entire 1/4 quadrant of the sphere... technically speaking, (and just to challenge adam a little), you should cut out the volume that isn't at the edge of the window, or just behind the edge... let's see you post an integration sign on hear beotch!   |
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Hein
Since 08 Mar 2005
1314 Posts
Possessed
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| Fri Aug 31, 07 9:11 am |
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-always good to check the math.
comparisons are always easy in the noggin.
All like terms; pi, 4/3 and the 1/4 (since we're
only dealing with one forth of a sphere) drop out
of both sides. so all you have left is the comparison
of two numbers cubed:
18*18*18 vs 23*23*23
The size of the usable wind window has no effect on
the comparison.
Amazing, those exponents, aren't they!?
Last edited by Hein on Fri Aug 31, 07 9:16 am; edited 2 times in total |
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genek
Since 21 Jul 2006
2165 Posts
East Po
KGB
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| Fri Aug 31, 07 9:12 am |
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| If you know where to put your kite when riding by other people then the volume taken up is just your lines plus kite. If you fly your kite all over the window while people are trying to squeeze by then I'm sure you're getting in people's way in any case. If a nice rotation is set up then at least 6 people can ride in the pool in relative peace as we did many times when the slider was set up. I imagine the crowds plus kooks can very quickly make it all go to hell. Too bad the coast forecast looks like crap so there's no escaping to the waves... |
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blowhard
Since 26 Dec 2005
2027 Posts
Windward
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| Fri Aug 31, 07 9:17 am |
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So then
Bulae is on the team?
embarassing the responses to his first posts |
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Kataku2k3
Since 14 Aug 2005
3753 Posts
Los Angeles, CA
Videographer
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| Fri Aug 31, 07 10:01 am |
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| Hein wrote: | -always good to check the math.
comparisons are always easy in the noggin.
All like terms; pi, 4/3 and the 1/4 (since we're
only dealing with one forth of a sphere) drop out
of both sides. so all you have left is the comparison
of two numbers cubed:
18*18*18 vs 23*23*23
The size of the usable wind window has no effect on
the comparison.
Amazing, those exponents, aren't they!?
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But Hein, that only takes half of the sweep right to left into consideration (or half of the volume). Excluding the kite height that I put in before, it'd be 36*18*18 and 46*23*23, right? I know, still not necessary, but I like to everything perfect! haha
Brett, I don't even wanna try! I just got out of Organic lab, now I've gotta pack, head up north, stop in Gervais to help a friend with his psycho Civic, then drive all the way out to Rufus! |
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forrest
Since 21 Jun 2005
4330 Posts
Hood River
Hick
CGKA Member
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| Sat Sep 01, 07 6:58 am |
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Guilty until proven innocent. 
| blowhard wrote: | So then
Bulae is on the team?
embarassing the responses to his first posts |
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